Robin Becker wrote: > eg for > >>> e = enumerate([0,1,2,3,4,5]) > >>> for i,a in e: > ... if a==3: break > ... > >>> for i,a in e: > ... print i,a > ... > 4 4 > 5 5 > >>> > > I think the second loop needs to start at 3 ie the split needs to be > start, limit semantics > > It would be nice to be able to fix it with a move back method.
I have to reread your previous post, it seems. Meanwhile: >>> e = enumerate(range(6)) >>> for i, a in e: ... if a == 3: ... for i, a in itertools.chain([(i, a)], e): ... print i, a ... break ... 3 3 4 4 5 5 Nesting the loops is necessary to handle empty lists and lists with no matching item correctly. Alternatively, you could set a 'found' flag. Another option: >>> def predicate((i, a)): return a != 3 ... >>> for i, a in itertools.dropwhile(predicate, enumerate(range(6))): ... print i, a ... 3 3 4 4 5 5 The extra function call might have a negative impact on performance, though. Peter -- http://mail.python.org/mailman/listinfo/python-list
