Andreas Müller:
> is there a construct like
> list.find (10, key='ID')
You can create yourself a little convenience function, or you can use
something like the following. First some testing code:
class C:
def __init__(self, id):
self.id = id
def __repr__(self):
return "<%s>" % self.id
seq = map(C, [1, -5, 10, 3])
print seq
That prints:
[<1>, <-5>, <10>, <3>]
Then you can find the index of all the classes with id = 10:
print [i for i, obj in enumerate(seq) if obj.id == 10]
It returns a [2]. If seq doesn't contain the requires object(s) it
returns an empty list.
Or just the first, working lazily:
print (i for i, obj in enumerate(seq) if obj.id == 10).next()
This time if seq doesn't contain the requires object(s) it raises a
StopIteration exception.
You can of course wrap that into a function, using seq and 10 as
arguments.
Bye,
bearophile
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