willie wrote:
> My code:
>
> from time import time
> def leibniz(terms):
>
>
> acc = 0.0
> num = 4.0 # numerator value remains constant in the series
> den = 1
> count = 0
> start_time = 0.0
> for aterm in range(terms):
> nextterm = num/den * (-1)**aterm # (-1) allows fractions to
> alternate
> #between a + and a - value
> acc = acc + nextterm
>
> den = den + 2 #denominator increments by 2
> count = count + 1
> #print(count,acc)
>
>
> print("Time elapsed: %f"%( time()- start_time))
> return acc
>
> The result I get is -- Time elapsed: 1227812482.390000 but I want to
> know the real time this code needed to run. Using a term value of
> 1000 I can see from the begining to end the actual time lapse is a
> little over 6 seconds. How do I get that value (6 + secs approx) as my
> time lapse.
start_time = time()
<do_something>
elapsed = time() - start_time
Diez
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