En Wed, 10 Dec 2008 16:59:16 -0200, brooklineTom <[EMAIL PROTECTED]>
escribió:
I want my exception handler to report the method that originally
raised an exception, at the deepest level in the call-tree. Let give
an example.
That's the default behavior, you don't have to do anything special.
import sys, traceback
class SomeClass:
def error(self):
"""Raises an AttributeError exception."""
int(3).zork()
def perform_(self, aSelector):
try:
aMethod = getattr(self, aSelector, None)
answer = apply(aMethod, [], {})
except: AttributeError, anAttributeErrorException:
aRawStack = traceback.extract_stack()
answer = None
(I assume you're using Python < 3.0)
Use the 3-names form of the except statement:
try:
aMethod = getattr(self, aSelector, None)
answer = aMethod()
except AttributeError, e, tb:
# the tb variable holds the traceback up to the error
# the same thing you see printed by Python when
# an unhandled error happens
answer = None
Alternatively, you can obtain the same thing with sys.exc_info()[2]
Remember to delete any reference to the traceback object as soon as you're
done with it; see http://docs.python.org/library/sys.html#sys.exc_info
--
Gabriel Genellina
--
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