Xah Lee wrote:
> > For those of you who don't know linear algebra but knows coding, this
> > means, we want a function whose input is a list of 3 elements say
> > {x,y,z}, and output is also a list of 3 elements, say {a,b,c}, with
> > the condition that
> >
> > a = x/Sqrt[x^2+y^2+z^2]
> > b = y/Sqrt[x^2+y^2+z^2]
> > c = z/Sqrt[x^2+y^2+z^2]
>
> > In lisp, python, perl, etc, you'll have 10 or so lines. In C or Java,
> > you'll have 50 or hundreds lines.
> >
> > Note, that the “norm” as defined above works for vectors of any
> > dimention, i.e. list of any length.
On Dec 10, 12:37 pm, [EMAIL PROTECTED] wrote:
> Ruby:
>
> def norm a
> s = Math.sqrt(a.map{|x|x*x}.inject{|x,y|x+y})
> a.map{|x| x/s}
> end
I don't know ruby, but i tried to run it and it does not work.
#ruby
def norm a
s = Math.sqrt(a.map{|x|x*x}.inject{|x,y|x+y})
a.map{|x| x/s}
end
v = [3,4]
p norm(v) # returns [0.6, 0.8]
The correct result for that input would be 5.
Also note, i wrote: «Note, that the “norm” as defined above works for
vectors of any dimention, i.e. list of any length.».
For detail, see:
• A Example of Mathematica's Expressiveness
http://xahlee.org/UnixResource_dir/writ/Mathematica_expressiveness.html
Xah
∑ http://xahlee.org/
☄
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