On 2008-12-11, chengang.beij...@gmail.com wrote:
> Hi,
>
> ord('\xf0') works and it only works for char. Do you know any way to
> convet
> '\xf0\xf0' and '\xf0\xf0\xff\xfe' to integer?
Perhaps you want the 'struct' module.
>>> struct.unpack('!hi', '\xf0\xf0\xf0\xf0\xff\xfe')
(-3856, -252641282)
help(struct) for more information
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Stephen Thorne
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