On Thu, 18 Dec 2008 17:42:28 -0800, Collin D wrote: > The corrected function is: > def quadratic_solution(a,b,c) > sol1 = -1*b + ((b**2 - 4*a*c)**.5)/2*a > sol1 = -1*b - ((b**2 - 4*a*c)**.5)/2*a > return (sol1, sol2) > > Squaring the -b would give you some strange solutions.... :D
So it would, but I didn't do that. Try again. You have a typo in the above: you've written "sol1" twice and there is no sol2. There is no difference between -1*b and -b (except that -b is probably a smidgen faster). In the quadratic formula, the -b must be divided by 2a as well as the discriminant. You're only dividing the discriminant. The *second* error has already been given away by Mark Dickson, who rightly points out that the quadratic equation is subject to round-off errors. The first error is still there :) (Hint: think about the precedence of operators and the need for brackets.) -- Steven -- http://mail.python.org/mailman/listinfo/python-list
