Hi,
I'm looking for a way to do this: I need to scan a text (paragraph or so) and look for occurrences of "<text-x> (<text-x>)". That is, if the text just before the open bracket is the same as the text in the brackets, then I have to delete the brackets, with the text in it.
Does anyone knows any way to achieve this?
The closest I've seen is (http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/305306) by Raymond Hettinger
>>> s = 'People of [planet], take us to your leader.' >>> d = dict(planet='Earth') >>> print convert_template(s) % d People of Earth, take us to your leader.
>>> s = 'People of <planet>, take us to your leader.' >>> print convert_template(s, '<', '>') % d People of Earth, take us to your leader.
"""
import re
def convert_template(template, opener='[', closer=']'):
opener = re.escape(opener)
closer = re.escape(closer)
pattern = re.compile(opener + '([_A-Za-z][_A-Za-z0-9]*)' + closer)
return re.sub(pattern, r'%(\1)s', template.replace('%','%%'))Cheers Maurice -- http://mail.python.org/mailman/listinfo/python-list
