Hey all, The following fails for me:
>>> from urllib2 import urlopen >>> f = >>> urlopen("http://groups.google.com/group/chromium-announce/feed/rss_v2_0_msgs.xml") Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.6/urllib2.py", line 124, in urlopen return _opener.open(url, data, timeout) File "/usr/lib/python2.6/urllib2.py", line 389, in open response = meth(req, response) File "/usr/lib/python2.6/urllib2.py", line 502, in http_response 'http', request, response, code, msg, hdrs) File "/usr/lib/python2.6/urllib2.py", line 427, in error return self._call_chain(*args) File "/usr/lib/python2.6/urllib2.py", line 361, in _call_chain result = func(*args) File "/usr/lib/python2.6/urllib2.py", line 510, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP Error 403: Forbidden >>> However, that _same_ url works perfectly fine on the same machine (and same network) using any of: * curl * wget * elinks * firefox Any helpful ideas ? cheers James -- -- "Problems are solved by method" -- http://mail.python.org/mailman/listinfo/python-list