I hv been developing a link scanner. Here the objective is to recursively scan a particular web site.
During this, my script met http://images.google.co.in/imghp?hl=en&tab=wi and passed it to the scan function, whose body is like this.. def scan(site): log=open(logfile,'a') log.write(site + "\n") site = "http://"; + site.lower() try: site_data = urllib.urlopen(site) parser = MyParser() parser.parse(site_data.read()) except(IOError),msg: print "Error in connecting site ", site print msg links = parser.get_hyperlinks() for l in links: log.write(l + "\n") But it throws a weird exception like this... Traceback (most recent call last): File "I:\Python26\linkscan1.py", line 104, in <module> main() File "I:\Python26\linkscan1.py", line 95, in main scan(lk) File "I:\Python26\linkscan1.py", line 65, in scan site_data = urllib.urlopen(site) File "I:\Python26\lib\urllib.py", line 87, in urlopen return opener.open(url) File "I:\Python26\lib\urllib.py", line 203, in open return getattr(self, name)(url) File "I:\Python26\lib\urllib.py", line 327, in open_http h = httplib.HTTP(host) File "I:\Python26\lib\httplib.py", line 984, in __init__ self._setup(self._connection_class(host, port, strict)) File "I:\Python26\lib\httplib.py", line 656, in __init__ self._set_hostport(host, port) File "I:\Python26\lib\httplib.py", line 668, in _set_hostport raise InvalidURL("nonnumeric port: '%s'" % host[i+1:]) httplib.InvalidURL: nonnumeric port: '' How can i handle this ??? -- http://mail.python.org/mailman/listinfo/python-list
