On Tue, Feb 17, 2009 at 8:19 AM, Kurda Yon <kurda...@yahoo.com> wrote: > r_new[1] = r[1]
This is the problem. "r" is a dictionary, a set of key/object pairs in essence. You're making the object that "r[1]" is pointing to a list, a mutable sequence of items. The expression "r[1]" will then return that list object and assign it to "r_new[1]" -- but now both these two dictionaries are pointing to the *same* object. Its not a copy of the object, but the same object itself which you're storing in two different dictionaries. If you want to store a copy of that list in r_new[1], you can use the copy module, or something like: r_new[1] = r[1][:] which uses list slices to return a copy of the specified list. HTH, --Stephen -- http://mail.python.org/mailman/listinfo/python-list
