hello
here is my code for sending the mail, using this code email is going
''''''''''''''''''''''''''''''''''''''''''''''''''''''''' CODE
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
import smtplib
from time import strftime
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.Utils import COMMASPACE, formatdate
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = " is sending the mail"
msg['From'] = 'jitu.ic...@myprivatedomain.com <jitu.ic...@domain.com>'
msg['Date'] = formatdate(localtime=True)
msg['To'] = 'jitu.ic...@gmail.com'
# Create the body of the message (a plain-text and an HTML version).
#text = "jitendra kya huy a!\nHow are you?\nHere is the link you
wanted:\nhttp://www.python.org";
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
This mail is send by wjitenrda
Here is the <a href="http://www.python.org";>link</a> you wanted.
</p>
</body>
</html>
"""
part2 = MIMEText(html, 'html')
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('smtp.myprivatedomain.com <http://name.com>')
s.login("user","password")
s.sendmail(msg['From'], msg['To'], msg.as_string())
s.close()
''''''''''''''''''''''''''''''''''''''''''''''''''''''''' CODE END
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
using this code i am able to send the email , but problem is
when i am changing
msg['To'] = "wrongu...@wrongdomain.comddsdjsdsdsjdh"
some wrong email then i am getting back failure notice in my inbox, which i
dont want..
is there any way so that i can identify wrong email during the run time
(when i am sending the email)
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http://mail.python.org/mailman/listinfo/python-list
