Hi everybody,
This example gives strange results:
########
def foo( l = [] ):
l2 = l
print l2
for i in range(10):
if i%2 == 0:
l2.append( i )
yield i
########
>>> [i for i in ut.foo()]
[]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> [i for i in ut.foo()]
[0, 2, 4, 6, 8]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> [i for i in ut.foo()]
[0, 2, 4, 6, 8, 0, 2, 4, 6, 8]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
...
How to explain this behavior? Why l is not [] when we enter again the
function foo()?
Thanks
Julien
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