En Fri, 27 Mar 2009 18:43:16 -0300, <[email protected]> escribió:
Python 2.5, PC.
I have a question about getting Python print to be able to recognize a
long type.
[...]
print 'TEST 3'
bird = bignumber(dog)
print 'type(bird) = %s' % type(bird)
print 'bird val = 0x%016X' % long(bird)
print 'bird val = 0x%016X' % bird
When I run this, I get:
[...]
TEST 3
type(bird) = <class '__main__.bignumber'>
bignumber.__long__ returning a <type 'long'>
bird val = 0x123456789ABCDEF0
bignumber.__int__ returning a <type 'long'>
Traceback (most recent call last):
File "C:\PythonTesting\bignmber.py, line 32, in <module>
print 'bird val = 0x%016X' % bird
TypeError: int argument required
Python print recognizes the local constant "dog", but it goes and
fetches the __int__ type from my object-based class, even though it's
value is a long. Then Python print doesn't expect a long to come back
and bombs out. I don't want to force the main program to cast the
long value getting returned. I know Python print can print a long,
but how can I make it select the __long__ instead of the __int__ ?
This bug was corrected in version 2.6 - see
http://bugs.python.org/issue1742669
If you have to stay with 2.5 I'm afraid any solution would require to
modify your code:
-- put long() around those arguments
-- "%s" % format_hex(val) (where format_hex does the long conversion)
-- redefine __str__ and use %s
--
Gabriel Genellina
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