f = urllib.urlopen("http://www.google.com";) s = f.read()It is working, but it's returning the source of the page. Is there anyway I can get almost a screen capture of the page?
This is the job of a browser -- to render the source HTML. As such, you'd want to look into any of the browser-automation libraries to hook into IE, FireFox, Opera, or maybe using the WebKit/KHTML control. You may then be able to direct it to render the HTML into a canvas you can then treat as an image.
Another alternative might be provided by some web-services that will render a page as HTML with various browsers and then send you the result. However, these are usually either (1) asynchronous or (2) paid services (or both).
-tkc -- http://mail.python.org/mailman/listinfo/python-list
