Thanks! That works! On Wed, Apr 15, 2009 at 6:14 PM, Chris Rebert <c...@rebertia.com> wrote:
> > On Wed, Apr 15, 2009 at 5:49 PM, Chris Rebert <c...@rebertia.com> wrote: > >> > >> On Wed, Apr 15, 2009 at 2:36 PM, Gaurav Moghe <moghe...@msu.edu> wrote: > >> > Hi, > >> > > >> > I am an amateur python user I wanted to know how do I know whether all > >> > the > >> > contents of a list are all same or all different? Now, I could > certainly > >> > write a loop with a counter. But is there a ready command for that? > >> > Checked > >> > a lot of docs and this mailing list, but didnt get anything > worthwhile. > >> > Would be glad to know. > >> > >> All same: > >> > >> list_1 == list_2 > >> > >> All different: > >> > >> all(x != y for x, y in zip(list_1, list_2)) > >> > On Wed, Apr 15, 2009 at 2:55 PM, Gaurav Moghe <moghe...@msu.edu> wrote: > > Hi Chris, > > > > Thanks for the reply. But I am interested in analysing the contents of > just > > one list. For example, > > > > list1=[1,2,3,4,5,6] > > So, the logical statement would probably be: > > if list1==(contains all same values), print "Same" ---->False > > if list1==(contains all different values), print "Different" ---->True > > > > I wanted to know here whether there is a command/function that can do > > exactly this. I hope I am more clearer than my last try! > > Ah, okay. Then you want: > > def all_same(lst): > return len(set(lst)) == 1 > > def all_different(lst): > return len(set(lst)) == len(lst) > > Note that these require all the elements of the list to be hashable. > > Cheers, > Chris > -- > I have a blog: > http://blog.rebertia.com >
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