Ciprian Dorin, Craciun napisał(a):
> Python way:
> def compare (a, b, comp = eq) :
> if len (a) != len (b) :
> return False
> for i in xrange (len (a)) :
> if not comp (a[i], b[i]) :
> return False
> return True
This is shorter, but I'm not sure if more pythonic:
def compare(a, b, compfunc=eq):
return all(compfunc(aelem, belem) for aelem, belem in zip_longest
(a, b, fillvalue=object()))Regards, Marek -- http://mail.python.org/mailman/listinfo/python-list
