Stef Mientki wrote:
<div class="moz-text-flowed" style="font-family: -moz-fixed">MRAB wrote:
Stef Mientki wrote:
hello,
I've pictures stored in a path relative to my python source code.
To get a picture, I need to know what path I'm on in each python
module.
I thought __file__ would do the job,
but apparently I didn't read the documentation carefully enough,
because file is the path to the module that called my module.
Any ways to get the path of "myself" ?
I'm not sure what you mean. I just did a quick test.
# File: C:\Quick test\child.py
print "name is %s" % __name__
print "file is %s" % __file__
# File: C:\Quick test\parent.py
import child
print "name is %s" % __name__
print "file is %s" % __file__
# Output:
name is child
file is C:\Quick test\child.py
name is __main__
file is C:\Quick test\parent.py
Yes, that's what I (and many others) thought,
but now put your code in a file, let's say the file "test.py",
and now run this file by :
execfile ( 'test.py' )
cheers,
Stef
</div>
Your original post asked about "what path I'm on in each python
module". Now it turns out you're using execfile(), which doesn't create
a module, it shortcircuits most of that.
So why not import the file as a module instead of using execfile?
Maybe using __import__() ?
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