On Jun 1, 4:46 pm, Stef Mientki <stef.mien...@gmail.com> wrote: > MRAB wrote: > > Stef Mientki wrote: > >> hello, > > >> I've pictures stored in a path relative to my python source code. > >> To get a picture, I need to know what path I'm on in each python module. > >> I thought __file__ would do the job, > >> but apparently I didn't read the documentation carefully enough, > >> because file is the path to the module that called my module. > > >> Any ways to get the path of "myself" ? > > > I'm not sure what you mean. I just did a quick test. > > > # File: C:\Quick test\child.py > > print "name is %s" % __name__ > > print "file is %s" % __file__ > > > # File: C:\Quick test\parent.py > > import child > > > print "name is %s" % __name__ > > print "file is %s" % __file__ > > > # Output: > > name is child > > file is C:\Quick test\child.py > > name is __main__ > > file is C:\Quick test\parent.py > > Yes, that's what I (and many others) thought, > but now put your code in a file, let's say the file "test.py", > and now run this file by : > execfile ( 'test.py' )
How can you execfile test.py without knowing the path to it? Whatever path you used to locate test.py is where the file is. If you're just execfiling a bare filename, then it's in the current directory, so just construct a relative pathname. Carl Banks -- http://mail.python.org/mailman/listinfo/python-list
