On Jun 2, 12:10 pm, oyster <lepto.pyt...@gmail.com> wrote:
> I have some strings, and I want to write them into a text files, one
> string one line
> but there is a requirement: every line has a max length of a certain
> number(for example, 10), so I have to replace extra SPACE*3 with
> SPACE*2, at the same time, I want to make the string looks good, so,
> for "I am123456line123456three"(to show the SPACE clearly, I type it
> with a number), the first time, I replace the first SPACE, and get "I
> am23456line123456three", then I must replace at the second SPACE
> block, so I get "I am23456line23456three", and so on, if no SPACE*3
> is found, I have to aString.replace(SPACE*2, SPACE).
> I hope I have stated my case clear.
>
> Then the question is, is there a nice solution?
>
> thanx
Assuming you want to crush all spaces into single space, you can:
while " " in s:
s = s.replace(" ", " ")
readable but not efficient. Better:
s = " ".join((x for x in s.split(" ") if x))
Note that this will strip leading and trailing spaces.
Or you can use regexps:
import re
s = re.sub(" {2,}", " ", s)
Iain
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