On 14 Jun., 16:00, Steven D'Aprano <st...@removethis.cybersource.com.au> wrote:
> Incorrect. Koch's snowflake, for example, has a fractal dimension of log > 4/log 3 ≈ 1.26, a finite area of 8/5 times that of the initial triangle, > and a perimeter given by lim n->inf (4/3)**n. Although the perimeter is > infinite, it is countably infinite and computable. No, the Koch curve is continuous in R^2 and uncountable. Lawrence is right and one can trivially cover a countable infinite set with disks of the diameter 0, namely by itself. The sum of those diameters to an arbitrary power is also 0 and this yields that the Hausdorff dimension of any countable set is 0. -- http://mail.python.org/mailman/listinfo/python-list
