On Wed, 17 Jun 2009 14:50:28 +1200, Lawrence D'Oliveiro <l...@geek-central.gen.new_zealand> wrote:
>In message <7x63ew3uo9....@ruckus.brouhaha.com>, wrote: > >> Lawrence D'Oliveiro <l...@geek-central.gen.new_zealand> writes: >> >>> I don't think any countable set, even a countably-infinite set, can have >>> a fractal dimension. It's got to be uncountably infinite, and therefore >>> uncomputable. >> >> I think the idea is you assume uniform continuity of the set (as >> expressed by a parametrized curve). That should let you approximate >> the fractal dimension. > >Fractals are, by definition, not uniform in that sense. Sorry if I've already posted half of this - having troubles hitting the toushpad on this little machine by accident. The fractal in question is a curve in R^2. By definition that means it is a continuous function from [a,b] to R^2 (with the same value at the two endpoints). Hence it's uniformly continuous. -- http://mail.python.org/mailman/listinfo/python-list
