Gustavo Narea wrote: > I've noticed that if I have a class with so-called "rich comparison" > methods > (__eq__, __ne__, etc.), when its instances are included in a set, > set.__contains__/__eq__ won't call the .__eq__ method of the elements > and thus > the code below: > """ > obj1 = RichComparisonClass()
How is RichComparisonClass implemented? Did you provide a __hash__() method such that obj1 == obj2 implies hash(obj1) == hash(obj2)? This is necessary for instances of the class to work properly with sets and dicts. Peter -- http://mail.python.org/mailman/listinfo/python-list
