Tim Pinkawa wrote:
On Mon, Jun 29, 2009 at 2:17 PM, Christian Heimes<li...@cheimes.de> wrote:
"if file in os.list()" is slow and not correct. You have to check if the
file is either a real file or a symlink to a file and not a directory or
special. Then you have to verify that the file has the executable bit, too.
I realize four lines of Python does not replicate the functionality of
which exactly. It was intended to give the original poster something
to start with.
I am curious about it being slow, though. Is there a faster way to get
the contents of a directory than os.listdir() or is there a faster way
to see if an element is in a list other than "x in y"? I believe
'which' will terminate once it finds any match, which mine does not,
but that can be fixed by adding a break after the print.
Have a look at os.path.isfile(), os.path.isdir() and os.path.islink().
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