phonky <[email protected]> writes:
> "itertools.count(): Make an iterator that returns consecutive integers
> starting with n"
>
> to me that sounds like that solves the increment issue, but what about
> future modules wanting to plug in a different
> numbering format, e.g. 205434.1234 or whatever?
You'd write a different generator for that, and use it instead of
itertools.count. E.g. (untested):
def different_gen():
a = 201593.0768 # initial number
while True:
yield '%.04f'% a
a += 123.4567 # increase in increments of this much
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