Miles Kaufmann wrote:
On Jul 15, 2009, at 1:43 PM, Jean-Michel Pichavant wrote:
Hrvoje Niksic wrote:
[snip]
Note that in Python A or B is in fact not equivalent to not(not A and
not B).
>>> l = [(True, True), (True, False), (False, True), (False, False)]
>>> for p in l:
... p[0] or p[1]
[snip]
Did I make twice the same obvious error ?
Try again with:
l = [('foo','bar'), ('foo', ''), ('', 'bar'), ('', '')]
-Miles
Didn't know that.
So if I resume:
- not 'foo' => False
- 'foo' or 'foo' => 'foo'
I may be missing something, but honestly, Guido must have smoked some
heavy stuff to write such logic, has he ?
Let's play again
False or 'foo' => 'foo'
False and 'foo' => False
So funny. I would have expected boolean operators to return a boolean
value. I should have read the f*** manual (this is an anticipated RTFM
counter-attack). Anyway Miles, thanks for the update.
JM
--
http://mail.python.org/mailman/listinfo/python-list
