On Aug 20, 5:18 pm, "Rami Chowdhury" <rami.chowdh...@gmail.com> wrote:
> > val = val.encode('hex')
>
> That's the crucial line -- it's returning a new integer, which you are
> re-binding to val. If you then did:
No, it returns another string, which still isn't the decimal
representation of the hex string. hex C => decimal 12
In [1]: '0C'.encode('hex')
Out[1]: '3043'
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