En Mon, 14 Sep 2009 23:33:05 -0300, tec <technic....@gmail.com> escribió:
or use filter
list=filter(lambda x: len(x)>0, list)
For strings, len(x)>0 <=> len(x) <=> x, so the above statement is
equivalent to:
list=filter(lambda x: x, list)
which according to the documentation is the same as:
list=filter(None, list)
which is the fastest variant AFAIK.
(Of course, it's even better to use the right split() call so there is no
empty strings to filter out in the first place)
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
