candide <[email protected]> wrote:
> Each of the following two functions mult1() and mult2() solves the
> question :
>
>
> # -----------------------------------------
> def mult1(a,b,m):
> return (x for x in range(a,b)[(m-a%m)%m:b:m])
>
> def mult2(a,b,m):
> return range(a,b)[(m-a%m)%m:b:m]
> # -----------------------------------------
>
>
Why are you slicing the result of range? Why not just pass appropriate
arguments to range or xrange directly?
def f(a,b,m):
return xrange((a+m-1)//m*m, b, m)
--
http://mail.python.org/mailman/listinfo/python-list
