import os
for filename in os.listdir("/usr/bbs/confs/september"):
#stat = os.stat(filename)
if filename.startswith("_"):
print filename
yes, as lallous mentioned, this can be done as a
list-comprehension/generator. If printing is all you want to do,
it's a nice and concise way:
print '\n'.join(fname for fname in os.listdir(loc) if
fname.startswith('_'))
If you're doing more processing than just printing it, your
for-loop is a better (clearer) way to go. If you have lots of
processing code, it might help to do the inverse:
for filename in os.listdir(location):
if not filename.startswith('_'): continue
lots()
of_processing()
and_your_complex_logic()
goes()
here()
It removes one level of indentation depth and makes it clear that
you don't intend to do anything with the non-leading-underscore
versions (rather than looking for a corresponding "else:" line
possibly screens later).
-tkc
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