On Oct 20, 3:51 pm, Peng Yu <pengyu...@gmail.com> wrote:
> Suppose I have the dirname/both.py, which has the definitions of
> classes A and B. I can use this module in the following code.
>
> #################
> import dirname.both
>
> a=dirname.both.A()
> b=dirname.both.B()
> ####################
>
> When the definitions of A and B become too long, it is better that I
> put them in two different files (to improve the maintainability), for
> example, dirname/A.py and dirname/B.py. Now, the code becomes
>
> #################
> import dirname.A
> import dirname.B
>
> a=dirname.A.A() #two A seems redundant
> b=dirname.B.B() #two B seems redundant
> ####################
>
> However, the last two lines are annoying to me, as 'A' and 'B' appears
> twice, which seems redundant.
>
> In C++, I can define namespace independent of file hierarchy (as shown
> in the following code). I'm wondering if there is a way to make the
> namespace separate from the file hierarchy in python.
>
> #include <dirname/A.hpp>
> #include <dirname/B.hpp>
>
> int main() {
> dirname::A a = dirname::A()
> dirname::B b = dirname::B()
>
> }
>
>
You can use:
from dirname.A import A
then you can use:
a = A()
Or there is other variant:
import dirname.A as dirname
a = dirname.A()
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