Robert Kern wrote:
On 2009-10-30 18:40 PM, Stef Mientki wrote:
Robert Kern wrote:
On 2009-10-30 12:19 PM, kj wrote:
How can a module determine the path of the file that defines it?
(Note that this is, in the general case, different from sys.argv[0].)
__file__
but for modules launched with execfile, __file__ doesn't exists.
Modules launched from execfile() using a properly initialized
namespace dict do.
interesting,
but how do I configure a "properly initialized namespace dict" (other
than my current namespace) ?
thanks,
Stef Mientki
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