Esmail schrieb:
Could someone help confirm/clarify the semantics of the [:] operator
in Python?
a = range(51,55)
############# 1 ##################
b = a[:] # b receives a copy of a, but they are independent
>
# The following two are equivalent
############# 2 ##################
c = []
c = a[:] # c receives a copy of a, but they are independent
No, the both above are equivalent. Both just bind a name (b or c) to a
list. This list is in both cases a shallow copy of a.
############# 3 ##################
d = []
d[:] = a # d receives a copy of a, but they are independent
This is a totally different beast. It modifies d in place, no rebinding
a name. So whover had a refernce to d before, now has a changed object,
whereas in the two cases above, the original lists aren't touched.
Of course, in your concrete example, the looks of it are the same. The
distinction is crucial in larger contexts.
Diez
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