In article <4b0a01a...@dnews.tpgi.com.au>, Lie Ryan <lie.1...@gmail.com>
wrote:
> The semantic of the in-place operator is something like:
> x += y
> becomes
> x = x.__iadd__(y)
>
> thus
> foo.bar += baz
> becomes
> foo.bar = foo.bar.__iadd__(baz)
>
> So the call sequence is,
> foo.__getattr__('bar') ==> x
> x.__iadd__(baz) ==> y
> foo.__setattr__('bar', y)
I don't get where the __setattr__() call comes from in this situation. I
thought the whole idea of __iadd__(self, other) is that it's supposed to
mutate self. So, why is there another assignment happening after the
__iadd__() call?
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