Esmail <ebo...@gmail.com> writes: > I dug around in the docs and found a named parameter that I can set > when I > call show. > > Definition: im.show(self, title=None, command=None) > > I installed irfanview and specified it/its path in the parameter, > but that didn't work either. It's really quite puzzling in the > case of Vista since that's been around for quite a few years now.
But I thought everyone was sticking their fingers in their ears and humming to try to forget Vista had been released, particularly now that Windows 7 is out :-) Perhaps there's an issue with the temporary file location. I don't have a Vista system to test on, but the show() operation writes the image to a temporary file as returned by tempfile.mktemp(), and then passes the name on to the external viewer. The viewing command is handed to os.system() with the filename embedded without any special quoting. So if, for example, the temporary location has spaces or "interesting" characters, it probably won't get parsed properly. One easy debugging step is probably to add a print just before the os.system() call that views the image (bottom of _showxv function in Image.py in my copy of 1.1.6). That way at least you'll know the exact command being used. If that's the issue, there are various ways around it. You could patch PIL itself (same function) to quote the filename when it is constructing the command. Alternatively, the tempfile module has a tempdir global you could set to some other temporary directory before using the show() function (or any other code using tempfile). -- David -- http://mail.python.org/mailman/listinfo/python-list