Rory Campbell-Lange wrote:
On 18/12/09, mattia (ger...@gmail.com) wrote:
Hi all, I have a dictionary that uses dates and a tuples ad key, value
pairs. I need to sort the values of the dict and insert everything in a
tuple. The additional problem is that I need to sort the values looking
at the i-th element of the list. I'm not that good at python (v3.1), but
this is my solution:
d = {1:('a', 1, 12), 5:('r', 21, 10), 2:('u', 9, 8)}
t = [x for x in d.values()]
def third(mls):
... return mls[2]
...
s = sorted(t, key=third)
pres = []
for x in s:
... for k in d.keys():
... if d[k] == x:
... pres.append(k)
... break
...
res = []
for x in pres:
... res.append((x, d[x]))
...
res
[(2, ('u', 9, 8)), (5, ('r', 21, 10)), (1, ('a', 1, 12))]
How about
mylist = [z for z in zip(list(d), list(d.values()))]
The Pythonic way for the above line is:
>>> mylist = list(d.items())
and then sort on your sort criteria, either i[0], i[0][1], i[0][2] or
i[0][3].
Rory
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