On Sun, Jan 10, 2010 at 10:21 PM, Sebastian <sebastian.lan...@gmx.de> wrote: > Hi there, > > I have an array x=[1,2,3] > > Is there an operator which I can use to get the result > [1,1,1,2,2,2,3,3,3] ? > > I tried x*3, which resulted in [1,2,3,1,2,3,1,2,3] > I also tried [[b,b,b] for b in x] which led to [[1,2,3],[1,2,3], > [1,2,3]], but this isn't what I want either.
from itertools import chain, repeat n = 3 stretched = list(chain(*[repeat(item, n) for item in x])) Cheers, Chris -- http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
