Nico Grubert wrote:
> Thanks a lot Stefan & Peter.
>
> I'm almost there (except sorting of umlauts does not work yet).
>
>
> import locale
locale.setlocale(locale.LC_ALL, "")
> def sorted(items, key):
> decorated = [(key(item), index, item) for index, item in
> enumerate(items)]
> decorated.sort()
> return [item[2] for item in decorated]
>
> items = [{'title':'the Ähnlich', 'id':1},
> {'title':'The Storm', 'id':2},
> {'title':'the bible','id':3},
> {'title':'The thunder', 'id':4}]
>
> print sorted(items, key=lambda d: locale.strxfrm(d.get('title')))
>
> -> [{'id': 2, 'title': 'The Storm'}, {'id': 4, 'title': 'The thunder'},
> {'id': 3, 'title': 'the bible'}, {'id': 1, 'title': 'the \xc4hnlich'}]
>
>
> The entry with the umlaut is the last item in but according to german
> umlaut rules it should be the first item in the result.
> Do I have to set anything with the locale module?
Adding the setlocale() call will suffice provided your script uses the same
encoding as your environment. If not something like
# -*- coding:utf-8 -*-
import locale
locale.setlocale(locale.LC_ALL, "")
encoding = locale.getlocale()[1]
def sorted(items, key):
decorated = [(key(item), index, item) for index, item in
enumerate(items)]
decorated.sort()
return [item[2] for item in decorated]
# book titles use unicode
items = [{'title':u'the Ähnlich', 'id':1},
{'title':u'The Storm', 'id':2},
{'title':u'the bible','id':3},
{'title':u'The thunder', 'id':4}]
def sortkey(item):
s = item["title"].encode(encoding)
return locale.strxfrm(s)
print sorted(items, key=sortkey)
may be a bit more robust. If your source code doesn't use UTF-8 you have to
modify the coding declaration at the top accordingly.
Peter
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