Adi Eyal <a...@digitaltrowel.com> wrote:
> Using regular expressions the answer is short (and sweet)
>
> mapping = {
> "foo" : "bar",
> "baz" : "quux",
> "quuux" : "foo"
> }
>
> pattern = "(%s)" % "|".join(mapping.keys())
> repl = lambda x : mapping.get(x.group(1), x.group(1))
> s = "fooxxxbazyyyquuux"
> re.subn(pattern, repl, s)
I'd use a def as being IMHO clearer than the lambda but YMMV. More
importantly I'd also escape the keys in case they contain any characters
special to regular expressions:
>>> mapping = {
"foo" : "bar",
"baz" : "quux",
"quuux" : "foo"
}
>>> import re
>>> pattern = "(%s)" % "|".join(re.escape(k) for k in mapping)
>>> def repl(x): return mapping[x.group(1)]
>>> s = "fooxxxbazyyyquuux"
>>> re.subn(pattern, repl, s)
('barxxxquuxyyyfoo', 3)
>>> re.sub(pattern, repl, s)
'barxxxquuxyyyfoo'
>>>
--
Duncan Booth http://kupuguy.blogspot.com
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