On Mon, Jan 18, 2010 at 8:31 PM, Chris Rebert <c...@rebertia.com> wrote: > On Mon, Jan 18, 2010 at 8:04 PM, tom <badoug...@gmail.com> wrote: >> hi... >> >> trying to figure out how to solve what should be an easy python/regex/ >> wildcard/replace issue. >> >> i've tried a number of different approaches.. so i must be missing >> something... >> >> my initial sample text are: >> >> Soo Choi</span>LONGEDITBOX">Apryl Berney >> Soo Choi</span>LONGEDITBOX">Joel Franks >> Joel Franks</span>GEDITBOX">Alexander Yamato >> >> and i'm trying to get >> >> Soo Choi foo Apryl Berney >> Soo Choi foo Joel Franks >> Joel Franks foo Alexander Yamato >> >> the issue i'm facing.. is how to start at "</" and end at '">' and >> substitute inclusive of the stuff inside the regex... >> >> i've tried derivations of >> >> name=re.sub("</s[^>]*\">"," foo ",name) >> >> but i'm missing something... >> >> thoughts... thanks > > "Some people, when confronted with a problem, think 'I know, I'll use > regular expressions.' Now they have two problems." > > Assuming your sample text is representative of all your test: > > new_text = "\n".join(line[:line.index('<')] + line[line.rindex('>')+1:] for > line in your_text.split('\n'))
Erm, remembering to intersperse the "foo" (should be all 1-line, bloody Gmail): new_text = "\n".join(line[:line.index('<')] + " foo " + line[line.rindex('>')+1:] for line in your_text.split('\n')) Or just use alex23's method, which seems all-round superior. :-) Cheers, Chris -- http://mail.python.org/mailman/listinfo/python-list