On Fri, 29 Jan 2010 12:13:50 +1100, Ben Finney wrote:
> Paul Rubin <no.em...@nospam.invalid> writes:
>
>> Ben Finney <ben+pyt...@benfinney.id.au> writes:
>> > So how should I be sorting a list with entries of “unequal types”
>> > such that it will work in Python 3?
>>
>> Um, what ordering do you want?
>
> The same ordering I'd get in Python 2; that is, determined by the types
> of the elements.
The ordering has not been consistent across minor versions of Python 2:
$ python2.0
Python 2.0.1 (#1, Jan 14 2010, 15:43:17)
[GCC 4.1.2 20070925 (Red Hat 4.1.2-27)] on linux2
Type "copyright", "credits" or "license" for more information.
>>> L = [None, {}, [], 1, "x"]
>>> L.sort()
>>> L
[1, None, {}, [], 'x']
$ python2.6
Python 2.6.1 (r261:67515, Dec 24 2008, 00:33:13)
[GCC 4.1.2 20070502 (Red Hat 4.1.2-12)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> L = [None, {}, [], 1, "x"]
>>> L.sort()
>>> L
[None, 1, {}, [], 'x']
Python has never guaranteed a particular ordering for unequal types, only
that it would be consistent between repeated calls to sort.
--
Steven
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