Chris Rebert <c...@rebertia.com> writes: > get_popular_name would have the type: IO () -> IO String
I don't know if it makes the explanation any clearer, but I think that isn't quite right. The Python version would have type String -> IO String. The parameterless Haskell version would just be an I/O action, with type IO String. IO () is not really involved. -- http://mail.python.org/mailman/listinfo/python-list
