On 2 feb, 16:55, Arnaud Delobelle <arno...@googlemail.com> wrote: > Joan Miller <pelok...@gmail.com> writes: > > I've a main function called i.e. *foo()* which has a block of code > > that is repetead several times (for the error catching code and error > > reporting), but that code has a return to exit of *foo()* > > > ----------- > > foo(): > > ... > > if self.background: > > _log.exception(str(error)) > > return ReturnCode.ERROR, None > > else: > > raise NameError(error) > > > ----------- > > > So I would tu put that code block into a separated function (*throw() > > *), but the problem is that it returns to the parent function (foo()). > > How to solve it? > > If I understand correctly, you can simply do this: > > def throw(...): > if ...: > ... > return ... > else: > raise ... > > def foo(): > ... > return throw(...) > > HTH > > I.e. if throw returns something, foo returns it as well. If throw > raises an exception, it will go through foo. Is this what you want? > > -- > Arnaud
Yes, that is it. It was more simple that I had thinked, thanks! -- http://mail.python.org/mailman/listinfo/python-list