On 5/10/05, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > Hello NG, > > it is probably a beginner question, but I didn't solve it without > for-loops, and I am unable to determine if there is a faster way (probably > using some built-in function) to do this task. I have to speed up a > wxPython code that uses a lot of string concatenation (and uses these > strings to build some Fancy StaticText Controls). I found a way, but I need > a little bit of help from you, NG. > > If I simplify the problem, suppose I have 2 lists like: > > a = range(10) > b = range(20,30) > > What I would like to have, is a "union" of the 2 list in a single tuple. In > other words (Python words...):
well a "union" can be obtained with: >>> z = range(10) + range(20, 30) >>> z [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29] > > c = (0, 20, 1, 21, 2, 22, 3, 23, 4, 24, 5, 25, ..... Alternating the items can be done by: >>> [z[((i%2)*(len(z/2)))+i/2] for i in range(len(z))] [0, 20, 1, 21, 2, 22, 3, 23, 4, 24, 5, 25, 6, 26, 7, 27, 8, 28, 9, 29] Or in a slightly different format: >>> zip(range(10), range(20, 30)) [(0, 20), (1, 21), (2, 22), (3, 23), (4, 24), (5, 25), (6, 26), (7, 27), (8, 28) , (9, 29)] > Sorry if it seems an homework assignment. It'd be one heck of a short homework assignment. I hope you've read the python tutorial at http://docs.python.org/tut/tut.html ; it'll help you a lot to go through it a couple times. Peace Bill Mill bill.mill at gmail.com -- http://mail.python.org/mailman/listinfo/python-list
