Jonathan Gardner wrote: > On Feb 18, 4:28 am, lallous <elias.bachaal...@gmail.com> wrote: >> f = [lambda x: x ** n for n in xrange(2, 5)] > > This is (pretty much) what the above code does. > >>>> f = [] >>>> n = 2 >>>> f.append(lambda x: x**n) >>>> n = 3 >>>> f.append(lambda x: x**n) >>>> n = 4 >>>> f.append(lambda x: x**n) >>>> n = 5 >>>> f.append(lambda x: x**n) > > Now, when you call f[0], you are calling "lambda x: x**n". What is > "n"? >
If you use a newer version of python (>= 2.5), then you might want to look at functools.partial. > def pow(a,n): > return a ** n > > f = [functools.partial(pow,n=n) for n in xrange(2, 5)] > Not sure, whether there's any (dis)advantage over > f = [lambda x,n=n: x ** n for n in xrange(2, 5)] or > f = [lambda x,n=n: pow(x,n) for n in xrange(2, 5)] bye N -- http://mail.python.org/mailman/listinfo/python-list
