On 04/07/10 00:16, Albert van der Horst wrote:
> In article <houv8a$ed9$0...@news.t-online.com>,
> Peter Otten <__pete...@web.de> wrote:
>> Pierre Quentel wrote:
>>
>>> I'm surprised nobody proposed a solution with itertools ;-)
>>
>> next(itertools.takewhile(lambda _: a == b, ["yes"]), "no")
>
> I could learn something here, if you explain it?
The signature for next() is:
next(iterator[, default])
In particular, pay attention the `default` parameter.
next() returns `default` if StopIteration is raised else it returns
iterator.__next__().
takewhile(predicate, ["yes"]).__next__() return the string "yes" if
predicate("yes") returns True else it raises StopIteration.
The predicate (lambda _: a == b) returns True if (a == b) is True
otherwise it returns False.
Put the next(), takewhile(), and the predicate together and you get an a
monster that returns `default` if a == b is False else "yes".
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