En Fri, 30 Apr 2010 23:16:04 -0300, Jimbo <nill...@yahoo.com> escribió:
Hello I have a relatively simple thing to do; move an object from one
to list into another. But I think my solution maybe inefficient &
slow. Is there a faster better way to move my stock object from one
list to another? (IE, without having to use a dictionary instead of a
list or is that my only solution?)
[code]
class stock:
code = "NULL"
price = 0
stock_list1 = []
stock_list2 = []
def transfer_stock(stock_code, old_list, new_list):
""" Transfer a stock from one list to another """
# is there a more efficient & faster way to
index = 0
for stock in old_list:
temp_stock = stock
if temp_stock.code == stock_code:
new_list.append(temp_stock)
del old_list[index]
index += 1
return new_list[/code]
I'd do that in two steps:
def transfer_stock(stock_code, old_list, new_list):
# find the indexes to transfer
indexes = [i for i,stock in enumerate(old_list)
if stock.code==stock_code]
# actually transfer them
for index in reversed(indexes):
stock = old_list[index]
new_list.append(stock)
del old_list[index]
# I would not return anything
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
