Astley Le Jasper ha scritto:
This is probably a really silly question but, given the example code
at the bottom, how would I get a single list?
What I currently get is:
('id', 20, 'integer')
('companyname', 50, 'text')
[('focus', 30, 'text'), ('fiesta', 30, 'text'), ('mondeo', 30,
'text'), ('puma', 30, 'text')]
('contact', 50, 'text')
('email', 50, 'text')
what I would like is:
('id', 20, 'integer')
('companyname', 50, 'text')
('focus', 30, 'text'),
('fiesta', 30, 'text'),
('mondeo', 30, 'text'),
('puma', 30, 'text'),
('contact', 50, 'text')
('email', 50, 'text')
SAMPLE CODE>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
def getproducts():
temp_list=[]
product_list=['focus','fiesta','mondeo','puma'] #usually this
would come from a db
for p in product_list:
temp_list.append((p,30,'text'))
return temp_list
def createlist():
column_title_list = (
("id",20,"integer"),
("companyname",50,"text"),
getproducts(),
("contact",50,"text"),
("email",50,"text"),
)
return column_title_list
for item in createlist():
print item
>>> def createlist():
... column_title_list = [
... ("id",20,"integer"),
... ("companyname",50,"text")]
... column_title_list += getproducts()
... column_title_list += [
... ("contact",50,"text"),
... ("email",50,"text")]
... return column_title_list
...
>>> for item in createlist():
... print item
...
('id', 20, 'integer')
('companyname', 50, 'text')
('focus', 30, 'text')
('fiesta', 30, 'text')
('mondeo', 30, 'text')
('puma', 30, 'text')
('contact', 50, 'text')
('email', 50, 'text')
>>>
bye
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