On Fri, Jun 11, 2010 at 10:11 PM, Ian Kelly <ian.g.ke...@gmail.com> wrote: > On Fri, Jun 11, 2010 at 9:31 PM, Vincent Davis <vinc...@vincentdavis.net> > wrote: >> Starting with an example. >> In [23]: x = [1,2,3,4,4,4,5,5,3,2,2,] >> In [24]: y = set(x) >> In [25]: y >> Out[25]: set([1, 2, 3, 4, 5]) >> In [26]: y2 = len(set(x)) >> In [27]: y2 >> Out[27]: 5 >> >> How would I do the above "y2 = len(set(x))" but have len(set()) in a >> dictionary. I know how to do .. >> In [30]: d = dict(s=set) >> In [32]: d['s'](x) >> Out[32]: set([1, 2, 3, 4, 5]) >> >> but not sure how to add the len() and thought maybe the answer in a >> lambda function. >> I know I could def a function but would prefer to keep it all on one line. > >>>> d = dict(s=lambda x: len(set(x))) >>>> d['s'](x) > 5
I must have been half asleep, I thought for sure I tried that. Well it works great this morning :) Thanks Vincent > > Cheers, > Ian > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
