I want to print filename and line number for debugging purpose. So far I only find how to print the line number but not how to print filename.
import inspect print inspect.currentframe().f_lineno I found inspect.getsourcefile(), but I have to supply a class name to it. I have searched online, but I don't find how to print the source filename. Would you please let me know? Also, always importing the inspect module and getting the frame and accessing the lineno from the frame is not very convenient to type. Is there a shorter way to access the line number (for example, in C++ and perl, __LINE__ can be used to access line number, which is much more convenient than the way that I found in python). -- Regards, Peng -- http://mail.python.org/mailman/listinfo/python-list
